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Question: > Oxygen occurs in nature as a mixture of isotopes \(16O,^{17}Oand^{18}O\)having atomic masses of \(...

Oxygen occurs in nature as a mixture of isotopes 16O,17Oand18O16O,^{17}Oand^{18}Ohaving atomic masses of 15.99515.995u 16.99916.999 u and 17.99917.999U and relative abundance of 99.763%,0.037%and0.200%99.763\%,0.037\% and0.200\% respectively.

What is the average atomic mass of oxygen?

A

15.999u15.999u

B

16.999u16.999u

C

17.999u17.999u

D

18.999u18.999u

Answer

15.999u15.999u

Explanation

Solution

(1) : Atomic mass of oxygen

=(99.763×15.995)+(0.037×16.999)+(0.200×17.999)100= \frac{(99.763 \times 15.995) + (0.037 \times 16.999) + (0.200 \times 17.999)}{100}

= 15.999u15.999u