Question

Molarity of H2SO4 is 18 M. Its density is 1.8 g/cm3, hence molality is

• A. 18
• B. 100
• C. 36
• D. 500

Answer 1

Answer: (D)

500

Answer 2

(4)

Let volume of solution is 1000 ml

moles of H2SO4 = 18

mass of H2SO4 = 18 ´ 98 = 1764 g

mass of solution = 1000 ´ 1.8 = 1800 g

mass of solvent = 1800 – 1764 = 36 g

molality $= \frac{18}{\left( \frac{36}{1000} \right)}$ = 500.