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Molarity equation of a mixture of solutions of same substance is given by

A

M1+V1×M2+V2×M3+V3+....=M1+M2+M3M_{1} + V_{1} \times M_{2} + V_{2} \times M_{3} + V_{3} + .... = M_{1} + M_{2} + M_{3}

B

M1V1+M2V2+M3V3+....=M(V1+V2+V3)M_{1}V_{1} + M_{2}V_{2} + M_{3}V_{3} + .... = M(V_{1} + V_{2} + V_{3})

C

M1V1+M2V2+M3V3+....M(1V1+1V2+1V3)\frac{M_{1}}{V_{1}} + \frac{M_{2}}{V_{2}} + \frac{M_{3}}{V_{3}} + ....M\left( \frac{1}{V_{1}} + \frac{1}{V_{2}} + \frac{1}{V_{3}} \right)

D

M1V1×M2V2×M3V3+...=M1(1V1×1V2×1V3)\frac{M_{1}}{V_{1}} \times \frac{M_{2}}{V_{2}} \times \frac{M_{3}}{V_{3}} + ... = M_{1}\left( \frac{1}{V_{1}} \times \frac{1}{V_{2}} \times \frac{1}{V_{3}} \right)

Answer

M1V1+M2V2+M3V3+....=M(V1+V2+V3)M_{1}V_{1} + M_{2}V_{2} + M_{3}V_{3} + .... = M(V_{1} + V_{2} + V_{3})

Explanation

Solution

(2) : Molarity of a mixture of solution of same substance is given by