Question

Match the column I with column II and mark the appropriate choice.

Column -I	Column –II
(A) Mass of H20.5produced when 0.5mole of zinc reacts withexcess of HCl	(i) 3.01 × 1023 Molecules
(B) Mass of all atoms of a compound with formula C70H22	(ii) 6.023 × 1023 Molecules
(C) Number of molecules in 35.5gCl2	(iii) 1.43 × 1021g
(D) Number of molecules in 64 g of SO2	(iv) 1g

• A. (A) $\rightarrow$ (ii), (B) $\rightarrow$ (i), (C) $\rightarrow$ (iv), (D) $\rightarrow$ (iii)

• B. (A)$\rightarrow$ (i), (B)$\rightarrow$ (ii), (C)$\rightarrow$ (iii), (D)$\rightarrow$ (iv)

• C. (A)$\rightarrow$ (iv), (B)$\rightarrow$ (iii), (C)$\rightarrow$ (i), (D)$\rightarrow$ (ii)
• D. (A)$\rightarrow$ (iv), (B)$\rightarrow$ (iii), (C)$\rightarrow$ (ii), (D)$\rightarrow$ (i)

Answer 1

Answer: (C)

(A)$\rightarrow$ (iv), (B)$\rightarrow$ (iii), (C)$\rightarrow$ (i), (D)$\rightarrow$ (ii)

Answer 2

(3) : (1) : $Zn + 2HCl \rightarrow Zncl_{2} + H_{2}$

1 mole of Zn will prodce 1 g of $H_{2}$

$0.5$mole of Zn will produce 1 g of $H_{2}$

(2) : $C_{70}H_{22}$

Molar mass = 862

Mass of atoms = 862/$6.023 \times 10^{23} = 1.43 \times 10^{- 21g}$

(3) : $70gofCl_{2} = 6.023 \times 10^{23}$molecules

$35.5gofCl_{2} = 3.01 \times 10^{23}$molecules

(4) : Molear mass of $so_{2} = 64 = 1$mole

64 g of $SO_{2} = 6.023 \times 10^{23}$molecules