Question

LPG is a mixture of n-butane &iso-butane. The volume of oxygen needed to burn 1 kg of LPG at NTP would be :

• A. 2240$\mathcal{l}$t
• B. 2510$\mathcal{l}$t
• C. 1000 $\mathcal{l}$t
• D. 500$\mathcal{l}$t

Answer 1

Answer: (B)

2510$\mathcal{l}$t

Answer 2

(2)

$C_{4}H_{\text{10 }} + \frac{\text{13}}{2}\text{ O2 }\overset{\quad\quad}{\rightarrow}\text{4 C}\text{O}_{2}\text{ + 5 }\text{H}_{2}\text{O }$

x ml n-butane

y ml isobutane

Volume of O2 = x ´ $\frac{13}{2}$ + y $\frac{13}{2}$