Question
Question: Match the reactions in List-I with the reagents in List-II: List-I (Reactions) (A) 2-iodo-2-methylb...
Match the reactions in List-I with the reagents in List-II:
List-I (Reactions) (A) 2-iodo-2-methylbutane → 2-methylbut-2-ene (B) tert-butyl alcohol → methyl tert-butyl ether (C) Cyclopentanol → Cyclopentanone (D) Cyclohex-2-en-1-ol → Cyclohex-2-en-1-one
List-II (Reagents) (I) (i) NaH, (ii) CH3Br (II) K+O−C(CH3)3, (CH3)3COH (III) CrO3Cl, CH2Cl2 (PCC in CH2Cl2) (IV) (i) TsCl, (ii) KI/acetone

A
(A)-(II), (B)-(I), (C)-(III), (D)-(III)
B
(A)-(I), (B)-(II), (C)-(IV), (D)-(III)
C
(A)-(II), (B)-(III), (C)-(I), (D)-(IV)
D
(A)-(IV), (B)-(I), (C)-(III), (D)-(II)
Answer
(A)-(II), (B)-(I), (C)-(III), (D)-(III)
Explanation
Solution
- (A) → (II): 2-iodo-2-methylbutane undergoes E2 elimination with a strong, bulky base like potassium tert-butoxide (KOtBu) to form 2-methylbut-2-ene.
- (B) → (I): The formation of methyl tert-butyl ether from tert-butyl alcohol is a Williamson ether synthesis. NaH deprotonates the alcohol to form the alkoxide, which then reacts with CH3Br.
- (C) → (III): Cyclopentanol (secondary alcohol) is oxidized to cyclopentanone using a mild oxidizing agent like Pyridinium Chlorochromate (PCC) in CH2Cl2.
- (D) → (III): Cyclohex-2-en-1-ol (secondary allylic alcohol) is oxidized to cyclohex-2-en-1-one using PCC in CH2Cl2.
