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Question: > In an experiment, 24 g of iron oxide on reduction with hydrogen gave 1.68 g of iron. In another ex...

In an experiment, 24 g of iron oxide on reduction with hydrogen gave 1.68 g of iron. In another experiment 2.92.9 g of iron oxide gave 2.092.09 g of iron on reduction.

Which law is illustrated from the above data?

A

Law of constant proportions

B

Law of multiple proportions

C

Law of reciprocal proportions

D

Law of conservation of mass

Answer

Law of constant proportions

Explanation

Solution

(1) : In first experiment,

2.42.4of iron oxide gave 1.681.68g of iron.

Mass of iron oxide=2.4g2.4g

Mass of iron =1.68g1.68g

Mass of oxygen

= 2.41.68=0.722.4 - 1.68 = 0.72

Ratio of masses of iron and oxygen =1.680.72=7:3= \frac{1.68}{0.72} = 7:3

In second experiment,

Mass of iron oxide

=2.9g2.9g

Mass of iron =2.09g2.09g

Mass of oxygen

= 2.92.09=0.812.9 - 2.09 = 0.81

Ratio of masses of iron and oxygen=2.090.81=7:3= \frac{2.09}{0.81} = 7:3