Question

In a reaction container, 100 g of hydrogen and 100 g of $Cl_{2}$are mixed for the formation of HCl gas. What is the limiting reagent and how much HCl is formed in the reaction?

• A. $H_{2}$ is limiting reagent and $36.5$ g of HCl are formed.

• B. $Cl_{2}$is limiting reagent and $102.8g$ of HCl are formed.

• C. $H_{2}$is limiting reagent and 142 g of HCl are formed.
• D. $Cl_{2}$ is limiting reagent and 73 g of HCl are formed.

Answer 1

Answer: (B)

$Cl_{2}$is limiting reagent and $102.8g$ of HCl are formed.

Answer 2

(2) : $\underset{2g}{H_{2}} + \underset{71g}{Cl_{2}} \rightarrow \underset{73g}{2HCl}$

2g of $H_{2}$reacts with 71 g of $Cl_{2}$

100 g of $H_{2}$will react with $\frac{71}{2} \times 100 = 3550$g of

$Cl_{2}$Hence, $Cl_{2}$is the limiting reagent.

71 g of $Cl_{2}$produces 73 g of HCl.

100 g of $Cl_{2}$will produce $\frac{73}{71} \times 100 = 102.8$g of HCl