Question

In a certain operation 358 g of TiCl4 is reacted with 96 g of Mg. Calculate % yield of Ti if 32 g of Ti is actually obtained [At. wt. Ti = 48, Mg = 24]

• A. 35.38 %
• B. 66.6 %
• C. 100 %
• D. 60 %

Answer 1

Answer: (A)

35.38 %

Answer 2

(1)

TiCl4 + 2Mg $\longrightarrow$Ti + 2MgCl2

Initial mole $\frac{358}{190}$= 1.88 $\frac{96}{24}$ = 4

final mole 0 4 – 2 × 1.88 1.88 2 × 1.88

wt of Ti obtained $\frac{358}{190}$= × 48

% yield $= \frac{\frac{32 \times 100}{358 \times 48}}{190}$ = 35.38 %