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Question: > If the concentration of glucose \((C_{6}H_{12}O_{6})\) in blood is \(0.9gL^{- 1}\), what will be t...

If the concentration of glucose (C6H12O6)(C_{6}H_{12}O_{6}) in blood is 0.9gL−10.9gL^{- 1}, what will be the molarity of glucose in blood?

A

5 M

B

50 M

C

0.005M0.005M

D

0.5M0.5M

Answer

0.005M0.005M

Explanation

Solution

(3) : Molarity

=WB(ing)MB(ingmol−1)×Volumeofsolution(inL)= \frac{W_{B}(ing)}{M_{B}(ingmol^{- 1}) \times Volumeofsolution(inL)}

=Conc.(ingL−1)MB(ingmol−1)=0.9180=0.005M= \frac{Conc.(ingL^{- 1})}{M_{B}(ingmol^{- 1})} = \frac{0.9}{180} = 0.005M

(∴MolarmassofC6H12O6=180gmol−1(\therefore MolarmassofC_{6}H_{12}O_{6} = 180gmol^{- 1})