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Question: > If 5.85 g of Nacl are dissolved in 90 g of Water, the mole fraction of Nacl would be-...

If 5.85 g of Nacl are dissolved in 90 g of Water, the mole fraction of Nacl would be-

A

0.1

B

0.01

C

0.2

D

0.0196

Answer

0.0196

Explanation

Solution

(4)

mole of NaCl = 5.8558.5=0.1\frac{5.85}{58.5} = 0.1

& mole of H2O = 9018=5\frac{90}{18} = 5

mole faction of NaCl = 0.15+0.1\frac{0.1}{5 + 0.1}

= 0.15.1\frac{0.1}{5.1}

= 0.0196