Question

If 1.5 moles of oxygen combine with Al to form Al2O3, the weight of Al used in the reaction is :

• A. 27 g
• B. 40.5 g
• C. 54g
• D. 81 g

Answer 1

Answer: (C)

54g

Answer 2

(3)

2 Al +$\frac{3}{2}$ O2 $\longrightarrow$ Al2O3

$\Rightarrow$weight of Al required = 2 × 27 = 54 g