How many oxygen atoms will be present in 88 g of (CO\_{2})? | CHEMISTRY - MOLE CONCEPT AND MOLAR MASSES | SolveeIt

How many oxygen atoms will be present in 88 g of $CO_{2}$ ?

$24.08 \times 10^{23}$

$44 \times 10^{23}$

$22 \times 10^{24}$

Answer

$24.08 \times 10^{23}$

Explanation

(1) : 1 mole of $CO_{2} = 44g$

88 g $CO_{2} = 2moles$

No. of oxygen atoms in 2 moles $= 2 \times 2 \times N_{A}$

$= 2 \times 2 \times 6.023 \times 10^{23} = 24.08 \times 10^{23}$

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