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Question: > How many number of molecules and atoms respectively are present in \(2.8\) litres of a diatomic ga...

How many number of molecules and atoms respectively are present in 2.82.8 litres of a diatomic gas at STP?

A

6.023×1023,7.5×10236.023 \times 10^{23},7.5 \times 10^{23}

B

6.023×1023,15×10226.023 \times 10^{23},15 \times 10^{22}

C

7.5×1022,15×10227.5 \times 10^{22},15 \times 10^{22}

D

15×1022,7.5×102315 \times 10^{22},7.5 \times 10^{23}

Answer

7.5×1022,15×10227.5 \times 10^{22},15 \times 10^{22}

Explanation

Solution

(3) : Number of molecules of gas at STP

=6.023×1023×2.822.4=7.5×1022= \frac{6.023 \times 10^{23} \times 2.8}{22.4} = 7.5 \times 10^{22}molecules

Number of atoms in diatomic molecule

=2×7.5×1022= 2 \times 7.5 \times 10^{22}

=15×1022= 15 \times 10^{22}atoms