Question

HCl is produced in the stomach which can be neutralized by $Mg(OH)_{2}$in the form of milk of magnesia. How much $Mg(OH)_{2}$ is required to neutralize one mole of stomach acid?

• A. $29.16g$
• B. $34.3g$
• C. $58.33g$
• D. $68.66g$

Answer 1

Answer: (A)

$29.16g$

Answer 2

(1) : $Mg(OH)_{2} + 2HCl \rightarrow MgCl_{2} + 2H_{2}O$

No. of moles of $Mg(OH)_{2}$required for 2 moles of HCl =1

No. of moles of $Mg(OH)_{2}$required for 1 mole of HCl = 0.5

Mass of $0.5$mol of

$Mg(OH)_{2} = 58.33 \times 0.5 = 29.16g$