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Question: > For every one \(37Cl\)isotope there are three \(35Cl\) isotopes in a sample of chlorine. What will...

For every one 37Cl37Clisotope there are three 35Cl35Cl isotopes in a sample of chlorine. What will be the average atomic mass of chlorine?

A

35

B

37

C

35.535.5

D

35.635.6

Answer

35.535.5

Explanation

Solution

: Atomic mass of chlorine=3×35+37×14=35.5\frac{3 \times 35 + 37 \times 1}{4} = 35.5