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Question

Question: The joint equation of pair of lines through (2, 3) and perpendicular to the coordinate axes is...

The joint equation of pair of lines through (2, 3) and perpendicular to the coordinate axes is

A

xy3x2y+6=0xy - 3x - 2y + 6 = 0

B

xy2x3y+6=0xy - 2x - 3y + 6 = 0

C

xy3x2y6=0xy - 3x - 2y - 6 = 0

D

xy+3x+2y6=0xy + 3x + 2y - 6 = 0

Answer

(a) xy3x2y+6=0xy - 3x - 2y + 6 = 0

Explanation

Solution

For a pair of lines through (2, 3) which are perpendicular to the coordinate axes the lines are:

  • vertical: x=2x = 2

  • horizontal: y=3y = 3

Their combined (joint) equation is obtained by writing:

(x2)(y3)=0    xy3x2y+6=0(x-2)(y-3)=0 \implies xy-3x-2y+6=0.