Question

CN– is oxidised by NO3– in presence of acid :

a CN– + b NO3– + c H+$\longrightarrow$ (a + b) NO + a CO2 + H2O

What are the whole number values of a, b, c in that order :

• A. 3, 7, 7
• B. 3, 10, 7
• C. 3, 10, 10
• D. 3, 7, 10

Answer 1

Answer: (D)

3, 7, 10

Answer 2

(4)

Equating number of O-atoms on both sides :

3b = a + b + 2a + c/2

$\therefore$ 4 b = 6 a + c

Also, from charge balance : c = a + b

$\therefore$a : b : c = 3 : 7 :10