Question

Calcium carbonate decomposes on heating to give calcium oxide and carbon dioxide. How much volume of $CO_{2}$ will be obtained by thermal decomposition of 50 g of $CaCO_{3}$?

• A. 1 L
• B. $11.2L$
• C. $44L$
• D. $22.4L$

Answer 1

Answer: (B)

$11.2L$

Answer 2

(2) : $\underset{100g}{CaCO_{3}} \rightarrow CaO + \underset{1mole = 22.4L}{Co_{2}}$

100 g of $CaCO_{3}$at STP gives $22.4L$of $CO_{2}$

50 g of $CaCO_{3}$will produce $\frac{22.4}{100} \times 50 = 11.2LofCO_{2}$