Question

Match List I with List II.

	List I		List II
A)	XeO₃	I)	sp³d, Linear
B)	XeF₂	II)	sp³, Trigonal pyramidal
C)	XeOF₄	III)	sp³d³, distorted octahedral
D)	XeF₆	IV)	sp³d², square planar
E)	XeF₄	V)	sp³d², square pyramidal

• A. A – II, B – I, C – V, D – III, E – IV
• B. A - II, B - III, C - V, D - I, E - IV
• C. A – II, B – V, C – III, D – I, E – IV
• D. A - III, B - II, C – I, D – V, E – IV

Answer 1

Answer: (A)

A – II, B – I, C – V, D – III, E – IV

Answer 2

The hybridization and molecular geometry of each compound are determined by calculating the steric number (number of sigma bonds + number of lone pairs) around the central Xenon atom.

• XeO₃: 3 sigma bonds + 1 lone pair = 4. Steric number 4 implies sp³ hybridization and trigonal pyramidal geometry.
• XeF₂: 2 sigma bonds + 3 lone pairs = 5. Steric number 5 implies sp³d hybridization and linear geometry.
• XeOF₄: 5 sigma bonds + 1 lone pair = 6. Steric number 6 implies sp³d² hybridization and square pyramidal geometry.
• XeF₆: 6 sigma bonds + 1 lone pair = 7. Steric number 7 implies sp³d³ hybridization and distorted octahedral geometry.
• XeF₄: 4 sigma bonds + 2 lone pairs = 6. Steric number 6 implies sp³d² hybridization and square planar geometry.

Matching these yields: A) XeO₃ - II) sp³, Trigonal pyramidal B) XeF₂ - I) sp³d, Linear C) XeOF₄ - V) sp³d², square pyramidal D) XeF₆ - III) sp³d³, distorted octahedral E) XeF₄ - IV) sp³d², square planar