Question

At NTP, 1 L of $O_{2}$ reacts with 3 L of carbon monoxide. What will be the volume of CO and $CO_{2}$ after the reaction?

• A. $1LCO_{2},1LCo$
• B. $2LCO_{2},2LCO$
• C. 1 L $CO_{2},2LCO$
• D. $2LCO_{2},1LCO$

Answer 1

Answer: (D)

$2LCO_{2},1LCO$

Answer 2

(4) : $\underset{2vol}{2CO} + \underset{1vol}{O_{2}} \rightarrow \underset{2vol}{2CO_{2}}$

1 vol of $O_{2}$reacts with 2 vol of CO

1 L of $O_{2}$reacts with 2 L of CO

CO left after reaction = 3 – 2 = 1L

1 L of $O_{2}$Produces 2 L of $CO_{2}$

Hence, after the reaction, CO = 1 L, $CO_{2} = 2L$