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Question: > An amount of 1.00 g of a gaseous compound of boron and hydrogen occupies 0.820 liter at 1.00 atm a...

An amount of 1.00 g of a gaseous compound of boron and hydrogen occupies 0.820 liter at 1.00 atm and at 30C. The compound is (R = 0.0820 liter atm mole-1 K-1; at. wt: H = 1.0, B = 10.8)

A

BH3

B

B4H10

C

B2H6

D

B3H12

Answer

B2H6

Explanation

Solution

(3)

PV = nRT

PV = 1M\frac{1}{M} RT