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Question: > A solution of glucose received from some research laboratory has been marked mole fraction x and m...

A solution of glucose received from some research laboratory has been marked mole fraction x and molality (m) at 100C. When you will calculate its molality and mole fraction in your laboratory at 240C you will find

A

Mole fraction (x) and molality (m)

B

Mole fraction (2x) and molality (2m)

C

Mole fraction (x/2) and molality (m/2)

D

Mole fraction (x) and (m ± dm) molalityb

Answer

Mole fraction (x) and molality (m)

Explanation

Solution

(1)

Molar fraction & molality is independent of temperature.