Question

A solution of FeCl3 is $\frac{M}{30}$ its molarity for Cl– ion will be :

• A. $\frac{M}{90}$
• B. $\frac{M}{30}$
• C. $\frac{M}{10}$
• D. $\frac{M}{5}$

Answer 1

Answer: (C)

$\frac{M}{10}$

Answer 2

(3)

Molarity of Cl– = 3 (molarity of FeCl3)

$= 3\left( \frac{M}{30} \right) = \frac{M}{10}$.