Question

A mixture having 2 g of hydrogen and 32 g of oxygen occupies how much volume at NTP?

• A. $44.8L$
• B. $22.4L$
• C. $11.2L$
• D. $67.2L$

Answer 1

Answer: (A)

$44.8L$

Answer 2

(1) : 2g of $H_{2}$= 1 mole, 32 g of $O_{2}$=1 mole

Total volume of 2 moles of gases at NTP= $2 \times 22.4L$=$44.8L$