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Question: > A gaseous hydrocarbon gives upon combustion 0.72 g of water and 3.08 g. of CO2. The empirical form...

A gaseous hydrocarbon gives upon combustion 0.72 g of water and 3.08 g. of CO2. The empirical formula of the hydrocarbon is :

A

C2H4

B

C3H4

C

C6H5

D

C7H8

Answer

C7H8

Explanation

Solution

(4)

18g H2O contains 2g H

\therefore 0.72 g H2O contains 0.08 gH.

44 g CO2 contains 12g C

\therefore 3.08 g CO2 contains 0.84 g C

\therefore C : H = 0.8412:0.081\frac{0.84}{12}:\frac{0.08}{1} = 0.07 : 0.08

= 7 : 8

\therefore Empirical formula = C7H8