Question

3g of a hydrocarbon on combustion in excess of oxygen produces 8.8 g of CO2 and 5.4 g of H2O. The data illustrates the law of :

• A. Conservation of mass
• B. Multiple proportions

• C. Constant proportions
• D. None of these

Answer 1

Answer: (A)

Conservation of mass

Answer 2

(1)

weight of CO2 = 8.8 gm

mole of CO2 =$\frac{8.8}{44}$ = 0.2

mole of C = 0.2

wt. of C = 0.2 × 12 = 2.4 g

mole of H2O = $\frac{5.4}{18}$ = 0.3

so mole of ‘H2’ = 0.3

wt. of hydrogen = 0.3 × 2 = 0.6

wt. of carbon + hydrogen = 2.4 + 0.6 = 3

= Initial wt. of hydrocarbon

$\therefore$ It illustrate law of conservation of mass.