Question

$+ 2C$ and $+ 6C$ two charges are repelling each other with a force of $12N$. If each charge is given $- 2C$ of charge, then the value of the force will be

• A. $4N$ (Attractive)
• B. $4N$ (Repulsive)
• C. $8N$ (Repulsive)
• D. Zero

Answer 1

Answer: (D)

Zero

Answer 2

Resultant charges after adding the – 2C be $( - 2 + 2) = 0$ and $( - 2 + 6) = + 4C$ ⇒ F$= \frac{kQ_{1}Q_{2}}{r^{2}} = k \times \frac{0 \times 4}{r^{2}} = 0$

$( - 2 + 6) = + 4C$ ⇒ F$= \frac{kQ_{1}Q_{2}}{r^{2}} = k \times \frac{0 \times 4}{r^{2}} = 0$)