Solveeit Logo

Question

Question: > \(2.82\)g of glucose is dissolved in 30 g of water. The mole fraction of glucose in the solution i...

2.822.82g of glucose is dissolved in 30 g of water. The mole fraction of glucose in the solution is.

A

0.010.01

B

0.990.99

C

0.520.52

D

1.661.66

Answer

0.010.01

Explanation

Solution

(1) : No. of moles of glucose =

wM=2.82180=0.01567\frac{w}{M} = \frac{2.82}{180} = 0.01567

No. of moles of water

=wM=3018=1.667= \frac{w}{M} = \frac{30}{18} = 1.667

Total no, of molesd of solution= 0.01567+1.667=1.6830.01567 + 1.667 = 1.683

Mole fraction of glucose =

0.015671.683=0.0093=0.01\frac{0.01567}{1.683} = 0.0093 = 0.01