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Question: > \(18.72\) g of a substance ‘X’ occupies 1.81\(cm^{3}\). What will be its density measured in corre...

18.7218.72 g of a substance ‘X’ occupies 1.81cm3cm^{3}. What will be its density measured in correct significant figures?

A

10.3gcm−310.3gcm^{- 3}

B

10.34gcm−310.34gcm^{- 3}

C

10.4gcm−310.4gcm^{- 3}

D

10.3425gcm−310.3425gcm^{- 3}

Answer

10.3gcm−310.3gcm^{- 3}

Explanation

Solution

(1) : Density

= MassVolume=18.721.81=10.34gcm−3\frac{Mass}{Volume} = \frac{18.72}{1.81} = 10.34gcm^{- 3}

Since volume contains 3 significant figures hence answer will be 10.3gcm−310.3gcm^{- 3}