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Question: > 0.48 g of a sample of a compound containing boron and oxygen contains \(0.192\) g of boron and \(0...

0.48 g of a sample of a compound containing boron and oxygen contains 0.1920.192 g of boron and 0.2880.288 g of oxygen. What will be the percentage composition of the compound?

A

60%60\% and 40% B and O respectively

B

40% and 60% B and O respectively

C

30% and 70% B and O respectively

D

70% and 30% B and O respectively

Answer

40% and 60% B and O respectively

Explanation

Solution

(2) : Mass of compound taken= 0.48g0.48g

Mass of boron in sample = 0.192g0.192g

Mass of oxygen in sample =0.288g0.288g

Percentage of B=0.1920.48×100=40%\frac{0.192}{0.48} \times 100 = 40\%

Percentage of O = 0.2880.48×100=60%\frac{0.288}{0.48} \times 100 = 60\%