Question
Question: \(- \sec x - \tan x + x + c\)...
−secx−tanx+x+c
A
∫sin2xcos2xdx=
B
tanx+cotx+c
C
cotx−tanx+c
D
tanx−cotx+c
Answer
∫sin2xcos2xdx=
Explanation
Solution
logsec(logx)+c
logcosec(logx)+c.
−secx−tanx+x+c
∫sin2xcos2xdx=
tanx+cotx+c
cotx−tanx+c
tanx−cotx+c
∫sin2xcos2xdx=
logsec(logx)+c
logcosec(logx)+c.