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Question: \(- E_{oxid}\) values of \(\rightarrow\) is \(\rightarrow\), of \(\rightarrow\) is \(\rightarrow\) a...

Eoxid- E_{oxid} values of \rightarrow is \rightarrow, of \rightarrow is \rightarrow and \rightarrow is \rightarrow. Which of the following statements is correct .

A

\rightarrow will reduce \rightarrow

B

\rightarrow will reduce \rightarrow

C

\rightarrow oxidises \rightarrow

D

\rightarrow oxidises \rightarrow

Answer

\rightarrow will reduce \rightarrow

Explanation

Solution

EZn++/Zno<EFe++/FeoE_{Zn^{+ +}/Zn}^{o} < E_{Fe^{+ +}/Fe}^{o}, so Zn will reduce Fe++Fe^{+ +}. ZnZn cannot reduce Mg2+Mg^{2 +} because EZn++/Zno>EMg++/MgoE_{Zn^{+ +}/Zn}^{o} > E_{Mg^{+ +}/Mg}^{o}

On similar reason Mg and ZnZncannot oxidize FeFe.