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Question: Consider the following radioactive decays I. $_{92}U \xrightarrow{-\alpha} _{90}Th$ and II. $_{90}...

Consider the following radioactive decays

I. 92Uα90Th_{92}U \xrightarrow{-\alpha} _{90}Th and

II. 90Thα88Ra_{90}Th \xrightarrow{-\alpha} _{88}Ra

In which case group of parent and daughter elements remains unchanged.

A

In (I)

B

In (II)

C

Both in (I) and (II)

D

None of the above

Answer

In (I)

Explanation

Solution

Let's analyze the two radioactive decays:

I. 92Uα90Th_{92}U \xrightarrow{-\alpha} _{90}Th: Both Uranium (U) and Thorium (Th) are part of the Actinide series. The Actinide series is typically considered part of Group 3. Thus, Group 3 -> Group 3, so the group remains unchanged.

II. 90Thα88Ra_{90}Th \xrightarrow{-\alpha} _{88}Ra: Thorium (Th) is part of the Actinide series (Group 3). Radium (Ra) is an Alkaline Earth Metal (Group 2). Thus, Group 3 -> Group 2, so the group changes.

Therefore, the group of parent and daughter elements remains unchanged only in case (I).