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Question

Question: \(- 3(\tan x)^{1/3} + c\)...

−3(tan⁡x)1/3+c- 3(\tan x)^{1/3} + c

A

−3(tan⁡x)−1/3+c- 3(\tan x)^{- 1/3} + c

B

3(tan⁡x)−1/3+c3(\tan x)^{- 1/3} + c

C

(tan⁡x)−1/3+c(\tan x)^{- 1/3} + c

D

∫cos⁡5x 6mudx=\int_{}^{}{\cos^{5}x\mspace{6mu} dx =}

Answer

(tan⁡x)−1/3+c(\tan x)^{- 1/3} + c

Explanation

Solution

Put ∫dx4cos⁡32x−3cos⁡2x=\int_{}^{}\frac{dx}{4\cos^{3}2x - 3\cos 2x} = then it reduces to

13log⁡[sec⁡6x+tan⁡6x]+c\frac{1}{3}\log\lbrack\sec 6x + \tan 6x\rbrack + c