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Question

Question: β - particle is emitted from the nucleus of mass number A with velocity u. Then, the recoil speed of...

β - particle is emitted from the nucleus of mass number A with velocity u. Then, the recoil speed of the nucleus will be

A

vmeAme\frac{vm_{e}}{A - m_{e}}

B

vmeA+me\frac{vm_{e}}{A + m_{e}}

C

4vA4\frac{4v}{A - 4}

D

vA\frac{v}{A}

Answer

vmeAme\frac{vm_{e}}{A - m_{e}}

Explanation

Solution

v. me= (A - me)v' or v' = vmeAme\frac{vm_{e}}{A - m_{e}}